Comments on: Timeago for C#

By: Richard O'Donnell

Richard O'Donnell — Tue, 20 Apr 2010 11:02:27 +0000

Rob,

Nope- I just thought the SO link would be useful for you, I didn’t realise you’d already seen it!

Oh well, it might be useful for someone finding your site via Google and wanting to look at other solutions to the problem.

By: Rob

Rob — Tue, 20 Apr 2010 10:57:52 +0000

Hey thanks Richard – did you see my comment at http://stackoverflow.com/questions/11/how-do-i-calculate-relative-time/111303#111303

By: Richard O'Donnell

Richard O'Donnell — Tue, 20 Apr 2010 10:43:40 +0000

Have a look at this: http://stackoverflow.com/questions/11/how-do-i-calculate-relative-time

By: Luke Venediger

Luke Venediger — Thu, 18 Feb 2010 12:58:31 +0000

Hi, thanks for this! I’ve modified it to be an extension method off TimeSpan:

public static string PrettyPrint(this TimeSpan t) { string[] NAMES = { "day", "hour", "minute", "second" };


      int[] ints = {

                         t.Days,

                         t.Hours,

                         t.Minutes,

                         t.Seconds

                     };
      double[] doubles = {

                               t.TotalDays,

                               t.TotalHours,

                               t.TotalMinutes,

                               t.TotalSeconds

                           };
      var firstNonZero = ints

          .Select((value, index) => new { value, index })

          .FirstOrDefault(x => x.value != 0);

      if (firstNonZero == null)

      {

        return "now";

      }

      int i = firstNonZero.index;

      string prefix = (i >= 3) ? "" : "about ";

      int quantity = (int)Math.Round(doubles[i]);
      Func Tense = (q, n) => q == 1

                                    ? "1 " + n

                                    : string.Format("{0} {1}s", q, n);

return prefix + Tense(quantity, NAMES[i]); }

By: IanR

IanR — Thu, 10 Sep 2009 08:00:27 +0000

Nice!
I did something similar a while ago, but without the elegance of this solution, obviously